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How to Solve Punnett Squares: Step-by-Step Genetics Guide

Master monohybrid genetic crosses, dominant vs recessive alleles, genotype ratios, and phenotype probabilities.

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Sparky Academic TeamCurriculum Specialist
7 min readUpdated 2026-10-17
Quick Summary / TL;DR

A Punnett square is a 2Γ—2 visual grid used to predict the genetic probabilities of offspring from two parents. Dominant alleles use CAPITAL letters (B) and override recessive alleles, which use lowercase letters (b). Split parental alleles along the top and left, combine them into the boxes, and calculate percentage probabilities!

Core Equation / Rule:
Probability of Offspring = Number of Matching Boxes4 Γ— 100%
πŸ’‘
🧬 Dominant shows with 1 copy; Recessive hides until you have 2 copies!
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The 4-Step Solving Process

1

Identify Parental Alleles & Genotypes

Homozygous = Same (BB or bb) \vert Heterozygous = Different (Bb)

Determine if parents are Homozygous Dominant (BB), Heterozygous (Bb), or Homozygous Recessive (bb).

πŸ’‘ Pro Tip: 'Homo' means same, 'Hetero' means different!
2

Draw a 2Γ—2 Grid and Label Parent Alleles

Parent 1: B and b (Top) \vert Parent 2: B and b (Left)

Place Parent 1's two alleles on top of the two columns, and Parent 2's alleles along the left rows.

πŸ’‘ Pro Tip: By Mendel's Law of Segregation, each reproductive gamete carries only one allele from each parent.
3

Fill the 4 Inner Offspring Boxes

Box 1: BB, Box 2: Bb, Box 3: Bb, Box 4: bb

Pull the letter from the top down and the letter from the left across into each meeting box.

πŸ’‘ Pro Tip: Always write the capital letter first: write 'Bb', never 'bB'.
4

Calculate Genotype and Phenotype Ratios

Genotype: 1 BB : 2 Bb : 1 bb \vert Phenotype: 3 Brown : 1 Blue (75% to 25%)

Count gene combinations (genotypes) vs visible physical traits (phenotypes). Each box = 25%.

πŸ’‘ Pro Tip: Genotype is the genetic code (letters); Phenotype is the physical appearance (look).

What is a Punnett Square?

A Punnett square is a simple graphical tool invented by geneticist Reginald Punnett in 1905. It visualizes all possible combinations of maternal and paternal alleles to predict the probability of traits in offspring.


Key Genetics Vocabulary You Must Know

  • β€’Allele: A version of a gene (represented by a single letter, like B or b).
  • β€’Dominant Allele (Capital letter, e.g. B): Strong trait. Only one copy is needed to show the physical trait.
  • β€’Recessive Allele (Lowercase letter, e.g. b): Weak trait. Can only show if both alleles are recessive (bb).
  • β€’Homozygous: Having two of the same alleles (BB = homozygous dominant, bb = homozygous recessive).
  • β€’Heterozygous: Having two different alleles (Bb = heterozygous carrier).
  • β€’Genotype: The letter combination (BB, Bb, or bb).
  • β€’Phenotype: The physical appearance (e.g. Purple flower or White flower).

Worked Example 1: Heterozygous Cross (Bb Γ— Bb)

This is the most famous cross in biology (Gregor Mendel's F2 generation).

Problem:

In pea plants, Purple flowers (P) are dominant over white flowers (p).

Cross two heterozygous purple plants (Pp Γ— Pp).

What are the genotype and phenotype probabilities?

Step 1: Set up the 2Γ—2 grid

Place Parent 1 (P and p) along the top, and Parent 2 (P and p) along the left:

Pp
PPP (Purple)Pp (Purple)
pPp (Purple)pp (White)

Step 2: Tally the 4 boxes (Genotypes)

Each box represents 25% (14) of the offspring:

  • β€’PP (Homozygous Dominant): 1 box = 25%
  • β€’Pp (Heterozygous): 2 boxes = 50%
  • β€’pp (Homozygous Recessive): 1 box = 25%

Genotype Ratio: 1 PP : 2 Pp : 1 pp

Step 3: Tally the physical traits (Phenotypes)

  • β€’Any plant with at least one P will be Purple:
PP$ (25%) + $Pp$ (50%) = **$75%$ Purple Flowers** ($34$) * Only $pp$ will be **White**: $pp$ = **$25%$ White Flowers** ($14$) **Phenotype Ratio:** **$3 Purple : 1 White$** --- <practice-widget /> --- ## Worked Example 2: Carrier Parent with a Recessive Parent ($Tt Γ— tt$) > **Problem:** > In guinea pigs, Black fur ($B$) is dominant and Brown fur ($b$) is recessive. > A heterozygous black guinea pig ($Bb$) mates with a homozygous brown guinea pig ($bb$). > What percentage of baby guinea pigs will have brown fur? ### Step 1: Draw the grid | | **B** | **b** | |:---:|:---:|:---:| | **b** | **Bb** (Black) | **bb** (Brown) | | **b** | **Bb** (Black) | **bb** (Brown) | ### Step 2: Analyze the 4 boxes * Two boxes are **$Bb$** (Black fur) $ ⟹ 24 = 50%
  • β€’Two boxes are bb (Brown fur) ⟹ 24 = 50%

Final Answer: There is exactly a 50% chance that an offspring will have brown fur.


Punnett Square Summary Cheat Sheet

Cross TypeParent GenotypesOffspring PhenotypesOffspring Genotype Ratio
Homozygous Dom Γ— RecessiveBB Γ— bb100% Dominant100% Bb
Heterozygous Γ— HeterozygousBb Γ— Bb75% Dominant, 25% Recessive1 BB : 2 Bb : 1 bb
Heterozygous Γ— RecessiveBb Γ— bb50% Dominant, 50% Recessive2 Bb : 2 bb (1:1)
Homozygous Dom Γ— HeterozygousBB Γ— Bb100% Dominant2 BB : 2 Bb (1:1)
⚠️WATCH OUT

Probability Does Not Guarantee Exact Litter Counts!

If two parents have a 25% chance of a blue-eyed child, having 4 children does NOT guarantee exactly 1 blue-eyed child. Each baby has an independent 25% chance, just like flipping a coin!

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